Wednesday, December 25, 2024

Master Fard Muhammad vs. Artificial Intelligence Computer 2024: The Supreme Wisdom Problem Book #7

 Supreme Wisdom
Problem Book

Problem #7

7. If one one-hundredth of a cubic inch contains two hundred million Atoms, the total Atmosphere weighs eleven and two-thirds quintillion pounds. One-third of eleven and two-thirds quintillion pounds equal Atoms. Mr. Muhammad cracked one Atom into ten million parts. Then Mr. Sharrieff wants to know how much the one-third of a cracked Atom weighs?

Problem 7 involves complex calculations involving weights and atoms. Let's break it down step-by-step:

Step 1: Weight of the Total Atmosphere

  • Total weight of the atmosphere: 11 and 2/3 quintillion pounds
  • In decimal form: 11.6667 quintillion pounds

Step 2: One-third of the Total Weight

  • One-third of the total weight:

11.66673=3.8889 quintillion pounds\frac{11.6667}{3} = 3.8889 \text{ quintillion pounds}

Step 3: Weight of a Cracked Atom

  • Mr. Muhammad cracked one atom into 10 million parts
  • One-third of a cracked atom’s weight:

3.8889 quintillion pounds10,000,000\frac{3.8889 \text{ quintillion pounds}}{10,000,000}

Calculation:

3.8889 quintillion pounds=3.8889×1018 pounds3.8889 \text{ quintillion pounds} = 3.8889 \times 10^{18} \text{ pounds}

3.8889×101810,000,000=3.8889×1011 pounds\frac{3.8889 \times 10^{18}}{10,000,000} = 3.8889 \times 10^{11} \text{ pounds}

So, one-third of a cracked atom weighs approximately 3.8889 × 10^{11} pounds.




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